Question

if possible explain as well.​

Answer 1

Answer:

14) d

15) c

Explanation:

14)

A two dimensional motion is the motion in 2D ( x-y ) plane . So, it can be a circle ⭕ .

Now, From given figure we see, that Velocity is not same in every point a , b , c as Magnitude is same but direction is different.

Also , to be known, velocity = displacement / time.

So, while travelling with constant velocity in a circle , at a certain time ,we will reach at (c) point where velocity is in opposite direction ⬇️ to the direction at point (a) ⬆️ . and thus average Velocity would be 0.

Hence ,

>> option a is incorrect ( false)

Since , acceleration is also have a direction and thus direction of velocity changes results in change in direction of acceleration.

Although having same magnitude , Velocity differs from point to point , thus , Acceleration is not necessarily 0 at every point.

>> option b is incorrect (false)

Displacement at point a , b , c arent equal as displacement is also a vector quantity and depends on direction .

>> option c is incorrect ( false)

In two dimensional motion, if instantaneous speed is a positive constant then equal path lengths are traversed in equal intervals of time.

>> option d is correct ( true)

15 )

From figure , we can see that velocity (direction components) differs from point to point . So, considering point a and c we can see that acceleration is not zero .

>> option a is incorrect

The acceleration of particle is not necessarily bounded .

>> option b is incorrect

Lets assume that, v = u i + w j ,

we know that a = dv/dt = (du/dt) i + (dw/dt) j

so , the acceleration of the particle is always in the same plane motion. ( x- y plane)

>> option c is correct.

Its not necessarily a uniform circular motion , it can be in any form having. velocity v constant.

>> option d is incorrect