Question

If potential energy of an electron in a hydrogen atom in first excited state is taken to be zero, kinetic energy (in ev) of an electron in ground state will be

Answer 1

TE in first excited state = -13.6/4 = -3.4 eV
PE in the first excited state = -6.8 eV (-PE = 2 X -TE)
For this to be zero, We must add 6.8 eV. So, add this 6.8 eV to all energy values to get the new values because shifting of zero or reference simply shifts all energy by the same value.
KE in ground state = 13.6 eV
So, in new system = 13.6 + 6.8 = 20.4 eV

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Answer 2

Answer:

Total Energy in first excited state = -13.6/4 = -3.4 eV

Potential Energy in the first excited state = -6.8 eV (-PE = 2 X -TE)

For this to be zero, add 6.8 eV to all energy values to get the new values..

Kinetic Energy in ground state = 13.6 eV

So, in new system = 13.6 + 6.8 = 20.4 eV

Hope it helps