If potential energy u= A-x^2/ B√x. (X in m ) find dimension of A and B
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Answer:
The units for U = (Ax^1/2) / (x+B) are in L^-1/2.
where:
L=Length.
The units for Potential Energy (M*(L/T^2)*L) = (M*L^2/T^2)
where:
M=Mass
L=Length
T=Time.
Since L^-1/2 is not equal to M*L^2 / T^2.
Therefore the units are not equal meaning the dimensions are different this means that U is not equal to Potential Energy in this case.
Explanation:
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