Question

if potential is increased by 10% and current also increased by 20% then how many % increase and decrease in power ?​

Answer 1

Answer:

hope help to you

Explanation:

let initial voltage is V and the current is I. So the power is VI and the resistance is V/I.

Now the resistance will remain the same which is equal to V/I and the current has now reached to 1.02I. So here we will be using 3 formulas to check the power.

Case 1: When P=VI

In this case P=V*1.02I which is equal to 1.02VI so the power increase is also 2 percent.

Case 2: When P=V^2/R

P=V^2/(V/I)=VI. So the power remains the same.

Case 3: When P=I^2*R

P=1.02*1.02*I*I*(V/I)=1.02VI. So the power increase is 2 percent again.

Now why case 2 failed to explain is because it is independent of current. We use that formula when changes in voltage is observed. So the power increase is 2 percent.

I think this is enough.