Question

If power dissipated in the 9 Ω resistor in the circuit shown is 36 W, the

potential difference across the 2 Ω resistor is​

Answer 1

Answer:

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Answer 2

Answer:

Power, P = VI = $\frac{V^{2} }{R}$

or, $V^{2}$ = PR

or, V = $\sqrt{P R}$ = $\sqrt{9 X 36}$ = 18V

9 Ohm and 6 Ohm resistors are in parallel, their equivalent resistance will be

$\frac{1}{R} = \frac{1}{9} + \frac{1}{6}$ = $\frac{6 + 9}{54} = \frac{15}{54}$

or, R = $\frac{54}{15}$ = $\frac{18}{5}$

Now, the voltage across this combination is 18V and the equivalent resistance of this combination is  $\frac{18}{5}$ ohm. SO, the current following through this equivalent resistor will be:

I = $\frac{V}{R}$ = $\frac{18}{\frac{18}{5} }$ = 5A

Now the equivalent resistor and 2Ohm resistors are in series. SO, same current will flow through them.

or, Current through 2Ohm resistor = 5A

So, voltage across 2Ohm resistor = I X R =  5 X 2 = 10V