Question

If power factor is 1/2 in a series RL circuit R = 100 Ω. If AC mains of 50 Hz is used then L is :-

Answer 1

power factor= resistance /impedence

impedence =√{(1/wL)²+ r²} here  

w=2pie f

2xpi x50=100pi=w

by solving we get L= 10^-4 / (pi√3)