Physics, asked by miracle1957, 1 year ago

If power of geyser is 2200j at 220v what is the minimum of the fuse

Answers

Answered by santy2
0

Given the voltage and the current the formula for getting power is given as :

Power = VI

Where :

V = potential difference measured in Volts.

I = Current measured in Amperes.

In this case we have been given the voltage and the power.

From this formula we can get the current of the fuse.

I = P/V

We do the substitution as follows :

P = 2200

V = 220 V

Applying the formula above we have :

2200/220 = 10 Amperes

The minimum current rating for the fuse is 10 A.

Similar questions