If power of geyser is 2200j at 220v what is the minimum of the fuse
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Given the voltage and the current the formula for getting power is given as :
Power = VI
Where :
V = potential difference measured in Volts.
I = Current measured in Amperes.
In this case we have been given the voltage and the power.
From this formula we can get the current of the fuse.
I = P/V
We do the substitution as follows :
P = 2200
V = 220 V
Applying the formula above we have :
2200/220 = 10 Amperes
The minimum current rating for the fuse is 10 A.
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