if power of lense is 15 then find its focal length step wise
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Power of lens is 15 D
by the formula
![f = \frac{1}{p} f = \frac{1}{p}](https://tex.z-dn.net/?f=f+%3D++%5Cfrac%7B1%7D%7Bp%7D+)
![focal \: length = \\ = > \frac{1}{15} m \\ = > \frac{1}{15} \times 100 \: cm \\ = > 6.67 \: cm \: focal \: length = \\ = > \frac{1}{15} m \\ = > \frac{1}{15} \times 100 \: cm \\ = > 6.67 \: cm \:](https://tex.z-dn.net/?f=focal+%5C%3A+length+%3D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B1%7D%7B15%7D+m+%5C%5C++%3D++%26gt%3B++%5Cfrac%7B1%7D%7B15%7D++%5Ctimes+100+%5C%3A+cm+%5C%5C++%3D++%26gt%3B+6.67+%5C%3A+cm+%5C%3A+)
by the formula
kumar00:
hi
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