If (PP)^2=MNOP, where M, N, O, P are distinct digits with O being odd. The values of P is/are
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Given : (PP)^2=MNOP, where M, N, O, P are distinct digits with O being odd.
To Find : The values of P
Solution:
(PP)² = MNOP
1² = 1 , 5² = 25 , 6² = 36 are only three combination
where (PP)² = MNOP will satisfy
Hence P can be 1 , 5 or 6
11² = 121 not possible
O is 2 hence not odd digit also only three digit number
55² = 3025
O is 2 hence not odd digit
66² = 4356
Hence P can be 6
M = 4 , N = 3 O = 5 which is Odd
Value of P is 6
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