If PQ=28cm, then find the perimeter of ∆PLM
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75
Step-by-step explanation:
since the length of tangents drawn from external point is equal
PQ=PT
PL+LQ=PM+MT
Since length of tangents drawn from point 'L' and 'M' are equal
PL+LN=PM+NM
Now,
Perimeter ∆PLM=PL+LM+PM
= PL+LN+NM+PM
= PL+LN+PL+LN
= 2(PL+LN)
= 2(PL+LQ)
= 2XPQ
=2XPQ
= 56Cm
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Answered by
22
Step-by-step explanation:
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