Math, asked by muditagarwal545, 19 days ago

If PQ||BC, AP =x m, PB=10m, AQ=(x-2)m, QC-6m,thenthe value of x is (x - 2) m Q (a) 3m 10 m 6 m (b) 4m B C (c) 5m (d) 8m​

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Answered by kartikkarki936
1

Step-by-step explanation:

GIVEN : in ∆ABC IF PQ//BC , AP =x m , PB = 10 m , AQ=( x-2) m , , QC = 6m , thenthe value of x is (x - 2) m

ATQ

PQ //BC so

AP/BP= AQ/CQ

x/10= x-2/6

x-2/10= x-2-(2)/6

x-2/10= x-4/6

BY cross multiplication method we get

6x-12=10x-40

4x= 28

x= 7

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