Question

IF PQ is a tangent to a circle at Q with centre O,then angle OQP is????....​

Answer 1

Answer:

As OQ⊥ PR

(radius ⊥ tangent) & AB∣∣PR

⇒AB⊥OL

and perpendicular from centre to chord bisects the chord.

⇒AL=BL,

∠QLB=∠QLA

& LQ=LQ\Rightarro$$ By SAS

congruency, ΔQLA≅ΔQLB

⇒∠AQL=∠BQL=20

o

(90

o

−70

o

)

⇒∠AQB=40

o

.

Answer 2

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pq is tangent and Oq is radius

we know that tangent is perpendiculatr to radius

Angle Opq = 90°

Angle OPQ is isoceles

• OP = PQ

Angle OQP = Angle POQ

SO,

angle Oqp = 1/2 X 90°

= 45°

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