Question

if PQ is a tangent to a circle of radius 5cm and PQ=12 cm ,Q is point of contact then OPis

Answer 1

Step-by-step explanation:

OPQ formed a right angled triangle where OP is hypotenuse , OQ is perpendicular and PQ is base....

BY PYTHAGORAS THEOREM,

OP^2=OQ^2+PQ^2

OP^2=5^2+12^2

OP^2=25+144

OP^2=169

OP =13cm

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Answer 2

Answer:

Step-by-step explanation:

OPQ formed a right angled triangle where OP is hypotenuse , OQ is perpendicular and PQ is base....

BY PYTHAGORAS THEOREM,

OP^2=OQ^2+PQ^2

OP^2=5^2+12^2

OP^2=25+144

OP^2=169

OP =13cm

I HOPE THIS ANSWER WILL HELP YOU SO PLZ MARK THIS ANSWER AS BRAINLIEST ANSWER. . . . .

Step-by-step explanation: