If PQ is a tangent to a circle with center
O and radius 6 cm such that angle PQO = 60° then find
the length of a tangent PQ and a line OQ
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Given : PQ is a tangent to a circle with center O and radius 6 cm such that angle PQO = 60°
To Find : length of a tangent PQ and a line OQ
Solution:
PQ is a tangent to a circle with center O
=> ∠OPQ = 90°
Radius = 6 cm
=> OP = 6 cm
∠PQO = 60°
in right angle triangle PQO
Tan60° = OP/PQ
=> √3 = 6/PQ
=> PQ = 2√3
Sin60° = OP/OQ
=>√3/2 = 6/OQ
=> OQ = 4√3
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the answer is given up ^^^^
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