if pq is parallel to bc, ap = 3xcm, pb = 24cm, aq= 3cm, qc = 18cm find x
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1
Answer:
We have
(
AC
AQ
)=
9
3
=
3
1
(
AB
AP
)=
10.5
3.5
=
3
1
In ΔAPQ & ΔABC
(
AC
AQ
)=(
AB
AP
)
& ∠PAQ=∠BAC
Thus ΔAPQ∼ΔABC by SAS criterion.
Hence (
AC
AQ
)=(
BC
PQ
) (by cpst)
⇒
3
1
=(
BC
4.5
)
⇒BC=13.5cm.
Step-by-step explanation:
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