Question

if PQ is tangent drawn from point P to a circle with center O and QOR is diameter of circle such that angle POR =120° , find angle OPQ​

Answer 1

Answer:

∠QOP + ∠POR = 180° ∠QOP + 120° = 180° ∠QOP = 180° - 120° ∠QOP = 60° In ΔPOQ ∠QOP + ∠OPQ + ∠PQO = 180° 60° + ∠OPQ + 90° = 180° 150° + ∠OPQ = 180° ∠OPQ = 180° - 150° ∠OPQ = 30°

Answer 2

Step-by-step explanation:

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