Question

If PQ is the diameter of a circle,whose centre isC (5, 8) and Q is (2,-3), find P​

Answer 1

Step-by-step explanation:

It is given that PQ is the diameter of circle and C is the centre of circle

then,

By using diastance formula

CQ =

$\sqrt{(x1 - x2) ^{2} +(y1 - y2) ^{2}$

$\sqrt(5 - 2 ^{2} } + (8 + 3) ^{2}$

we get ,√130 unit

CQ is the radius of circle

Diameter = 2r

diameter = 2√130

2 ✖ 11.40

22.8 is the diameter of circle

Hope it will help you...