if pq=ps,rq=rs show ∆pqr~∆psr and ∆rqt~∆rst
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Given : PQ = PS , RQ = RS
To Find : Show that ΔPQR ≅ Δ PSR and ΔRQT ≅ Δ RST
Solution:
Comparing ΔPQR and Δ PSR
PQ = PS ( given )
RQ = RS ( given )
PR = PR ( common)
=> ΔPQR ≅ Δ PSR ( SSS)
QED
Congruent Triangles: corresponding angles and sides are congruent
=> ∠PRQ = ∠PRS
=> ∠TRQ = ∠TRS ( ∵ T lies on PR)
Comparing ΔRQT and Δ RST
RT = RT ( common)
∠TRQ = ∠TRS ( shown above)
RQ = RS ( given )
=> ΔRQT ≅ Δ RST ( SAS)
QED
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