Question

if PQ=QR and /_Q is 80, find x

Answer 1

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In a $\tt{\triangle PQR}$, the sides PQ and QR are equal and /_Q is given as 80°. Also, /_P = x°. We wish to find the value of x.

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$\mathbb{GIVEN:}$

In a $\tt{\triangle PQR}$, PQ = QR

/_Q = 80°

Also, /_P = x

Since PQ = QR, /_P = /_R ( the angles opposite to equal sides are equal to one another, a property of triangles )

/_P = /_R = x

We know that :-

/_P + /_Q + /_R = 180° ( The Angle Sum Property of a triangle)

Solve this formed equation further

=》 2x + 80 = 180

Solve it further

=》 x = $\bf{50\degree}$

Thus, x = 50° if /_Q = 80°.