Math, asked by aditya127, 1 year ago

If pqr=1, then prove that [ 1/(1+p+q-1)] + [1/(1+q+r-1)] + [1/(1+r+p-1)] = 1. ....... plzz no google answers

Answers

Answered by abhi178
79
LHS = 1/[1 + p + q⁻¹] + 1/[1 + q + r⁻¹] + 1/[1 + r + p⁻¹]

1/[1 + p + q⁻¹] = 1/[1 + p + 1/q] = q/ [q + pq + 1] -------(1)

1/[1 + q + r⁻¹] = 1/[1 + q + 1/r ]
= 1/[1 + q + pqr/r ] {from pqr = 1}
= 1/[1 + q + pq] = 1/[q + pq + 1] --------(2)

1/[1 + r + p⁻¹] = pqr/[pqr + r + pqr/p]
= pqr/[pqr + r + qr] = pq/[pq + 1 + q] ------(3)

Add equations (1), (2) and (3)
q[1 + pq + q] + 1/[q + pq + 1] + PQ/[pq + 1 + q]
= [1 + pq + q]/[1 + pq + q] = 1
Hence , LHS = RHS proved//
Answered by Anonymous
51

Given :

1/[1 + p + q⁻¹] + 1/[1 + q + r⁻¹] + 1/[1 + r + p⁻¹]


1/[1 + p + q⁻¹] = 1/[1 + p + 1/q] = q/ [q + pq + 1] .............1


1/[1 + q + r⁻¹] = 1/[1 + q + 1/r ]


= 1/[1 + q + pqr/r ] {as pqr = 1}


= 1/[1 + q + pq] = 1/[q + pq + 1] .............2



1/[1 + r + p⁻¹] = pqr/[pqr + r + pqr/p]


= pqr/[pqr + r + qr] = pq/[pq + 1 + q] ............3



If we add (1), (2) and (3) :


q [1 + pq + q] + 1/[q + pq + 1] + pq/[pq + 1 + q]


= [1 + pq + q]/[1 + pq + q] = 1


PROVED !

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