Question

if∆PQR,If <P=2<Q=3<R,find the angles​

Answer 1

Answer:

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Answer 2

$\huge\underbrace{\pink{\tt{\diamond\;Solution:}}}$

Given,

PQR is a Triangle

☞ Angle P = 2(Angle Q) = 3(Angle R)

Let, Angle P = x°

Then, Angle Q = 2x° & Angle R = 3x°

$✯\;\boxed{\sf{Sum\;of\;all\;angles\;in\;a\;∆le = 180°}}$

$→\;\bf{x°+2x°+3x° = 180°}$

$→\;\bf{6x° = 180°}$

$→\;\bf{x° = {\cancel{\frac{180°}{6}}}}$

$→\;\bf{x° = 30°}$

◕➜ Angle P = x° ➝ $\fbox\red{30°}$

◕➜ Angle Q = 2x° ➝ $\fbox\green{60°}$

◕➜ Angle R = 3x° ➝ $\fbox\purple{90°}$

Hope It Helps You ✌️