If pqr in are in the AP then find the value of p q + R cube minus 8 Cube cube
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Answered by
18
p³ + r³ - 8q³ = -6pqr if pqr in are in the AP
Step-by-step explanation:
If p, q, r are in AP, then p³ + r³ – 8q³ is equal to
p q r in AP
=> q - p = r - q
=> 2q = p + r
Cubing both sides
=> 8q³ = p³ + r³ + 3pr(p + r)
p + r = 2q
=> 8q³ = p³ + r³ + 3pr(2q)
=> 8q³ = p³ + r³ + 6pqr
=> p³ + r³ - 8q³ = -6pqr
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Answered by
7
Answer:
Since p, q and r in AP
=> q - p = r - q
=> 2q = p + r
Cubing both sides
=> 8q³ = p³ + r³ + 3pr(p + r)
p + r = 2q
=> 8q³ = p³ + r³ + 3pr(2q)
=> 8q³ = p³ + r³ + 6pqr
=> p³ + r³ - 8q³ = -6pqr
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