Question

if pqr is a right and triangle right angle at q and qs perpendicular bisect pr. PQ =6 ps=4 find OS,RS and QR​

Answer 1

Answer:

QS=2√5

RS=4

QR=2√7

Step-by-step explanation:

As QS is perpendicular bisector of PR,

∴ RS=PS = 4

In right angle triangle PQS, PQ is the hypotenuse

Using Pythagoras theorem, PQ²=QS²+PS²

6²=QS²+4²

36=QS²+16

QS²=20

QS=√20=2√5

In right  angle triangle PQR, PR is the hypotenuse

But PR=RS+PS=4+4=8

∴ PR²=PQ²+QR²

8²=6²+QR²

64=36+QR²

QR²=64-36=28

QR=√28=2√7