Question

if PQR is the tangent to a circle at Q whose centre is O, AB is a chord parallel to PR and angle BQR=70, THEN angle AQB is equal to​

Answer 1

Answer:

PQR is a tangent and AB∥PQR

∠BQR=70

∴∠BAQ=∠BQR=70 (angles in the alternate segment are equal)

Also, AB∥PQR

∴∠ABQ=∠BQR=70 (ALTERNATE ANGLES)

Now, using angle sum property in △ABQ we get,

∠BAQ+∠ABQ+∠AQB=1800

=∠AQB=180−70−70

=40

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Step-by-step explanation: