If Δ PQR ∼ Δ LMN & PQ = 4 cm, QR = 5 cm, PR = 6 cm. Perimeter of Δ LMN is 90 cm then LM =?cm and MN =?cm
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Answered by
5
Answer:
LM = 24
MN = 30
Step-by-step explanation:
Consider 2 triangles PQR and LMN
given : PQR ~ LMN, PQ =4cm, QR = 5 cm, PR = 6cm, perimeter of LMN = 90
since, PQR ~ LMN,
4x + 5x + 6x = 90
15x = 90
x = 90/15
x = 6
LM = 4x = 4×6 = 24
MN = 5x = 5 × 6 = 30
hope u find this answer helpful
Answered by
2
Step-by-step explanation:
as we know in case of similar triangle
ratio of corresponding side length is always equal, here
pq/lm=qr/mn=pr/ln=constant x
4/lm=5/mn=6/ln=x
that implies lm=4/x
mn=5/x
lm=6/x
perimeter=90
4/x+5/x+6/x=90
15/x=90
x=1/6
lm=4×6/1=24
mn=5×6/1=30
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