Question

If ∆PQR <P = 2 <Q and <R = 3 <Q. Calculate the angles of ∆PQR

​

Answer 1

$\huge \fbox \pink{Answer:}$

Given:

$∠P = 2 ∠Q \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ... (1)$

$∠R = \frac{3}{2} ∠Q \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: .. (2)$

Also sum of angles of a triangle is 180 degree.

Also sum of angles of a triangle is 180 degree.From equation (1) and (2):

$⇒∠P + ∠Q + ∠R = 180°$

$⇒2∠Q + ( \frac{3}{2} )∠Q + ∠Q = 180°$

$⇒∠Q = \frac{180° \times 2}{9} = 40°$

$so , \: ∠P = 2(40°) = 80° \:$

$( \frac{ 3}{2} )20° = 60°$

$\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$