if PQRS is a quadrilateral ,then show that,
PQ+QR+RS+PS>(PR+QS)
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PQRS is a quadrilateral in which diagonal PR and QS intersect at a O . we know that sum of any two side of a triangle is greater than the third side . = 2( PR + QS ) > PQ+PS+RS + QR ( proved) .... The Brainliest Answer!
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