Math, asked by sunayanamalviya, 4 months ago

If PQRS is a quadrilateral then show that : PQ+QR+RS+PS> ( PR + QS )

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Answered by meghapatel722

Answer:

PQRS is a quadrilateral in which diagonal PR and QS intersect at a O . we know that sum of any two side of a triangle is greater than the third side . = 2( PR + QS ) > PQ+PS+RS + QR ( proved)

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If PQRS is a quadrilateral then show that : PQ+QR+RS+PS> ( PR + QS )​

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If PQRS is a quadrilateral then show that : PQ+QR+RS+PS> ( PR + QS )