Question

If pqrs is a rhombus, ps=3a+2,pq=4a-4 . find the value a

Answer 1

Answer:

We know that, in a rhombus all sides are equal. Given ps= 3a+2, pq= 4a-4. Since all the 4sides in a rhombus are equal, we get ps= pq, i.e 3a+2= 4a-4, 3a- 4a= -4-2, -a= -6, By applying minus sign (-) on both sides, we get a= 6. Hence the value of a=6units. Hope this helps you.