Question

if ∆ PQTbis right triangle with anger R=90°,then the value of cos(P+Q) is​

Answer 1

Answer:

p+ q is 90

think so not sure

Answer 2

△PQR is right angled at R then ∠R=90∘

cos(P+Q)=cos(180−R)  (Since sum of the angle in a triangle is 180)

⇒cos(P+Q)=cos(180−90)

⇒cos(P+Q)=cos90∘

∵cos90∘=0

∴cos(P+Q)=0

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