If PR 12cm QR = 6cmand Plegan then QM is
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QM = 4 cm if pr=12cm, qr=6cm and pl=8cm
Step-by-step explanation:
PR = 12 cm
PL = 8 cm
RL² = PR² -PL²
=> RL² = 12² - 8²
=> RL² = 144 - 64
=> RL² = 80
=> RL = 4√5 cm
Area of ΔPLR = (1/2) * 8 * 4√5 = 16√5 cm²
LQ = LR - RQ = 4√5 - 6
Area of Δ PLQ = (1/2) 8 * (4√5 - 6)
= 16√5 - 24 cm²
Area of ΔPQR = Area of ΔPLR - Area of Δ PLQ
=> Area of ΔPQR = 16√5 - (16√5 - 24) = 24 cm²
Area of ΔPQR = (1/2) * PR * QM = (1/2) * 12 * QM
= 6 QM
6 QM = 24
=> QM = 4 cm
Another method
Area of Δ PQR = (1/2) * QR * PL = (1/2) PR * QM
=> 6 * 8 = 12 * QM
=> QM = 4 cm
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