If PR>PQ and PS bisects angle QPR. Prove that angle PSR>angle PSQ
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Heyaa...☺☺✌
GIVEN => PR > PQ
TO PROVE => <PSR > <PSQ
PROOF => Since PR > PQ
So <PQR > <PRQ
[ angles opposite to greater sides are greater ]
Since PS is the bisector so.
<PQS > <PRS ................. ( 1 )
<QPS + <PQS = <PSR .............. ( 2 )
<PRS + <RPS = <PSQ .............. ( 3 )
From ( 1 ) keeping in ( 2 ) & ( 3 )
<QPS + <RPS = <P
<PQS > <PRS = <PSR = <PSQ
SO <PSR > <PSQ
Hence proved
Hope it helps u..☺☺✌
Thanks....❤❤
GIVEN => PR > PQ
TO PROVE => <PSR > <PSQ
PROOF => Since PR > PQ
So <PQR > <PRQ
[ angles opposite to greater sides are greater ]
Since PS is the bisector so.
<PQS > <PRS ................. ( 1 )
<QPS + <PQS = <PSR .............. ( 2 )
<PRS + <RPS = <PSQ .............. ( 3 )
From ( 1 ) keeping in ( 2 ) & ( 3 )
<QPS + <RPS = <P
<PQS > <PRS = <PSR = <PSQ
SO <PSR > <PSQ
Hence proved
Hope it helps u..☺☺✌
Thanks....❤❤
Anonymous:
ur wlcm...☺☺
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4
the answer is in the attachment
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