If pressure at half the depth of a lake is equal to 2/3 the
pressure at the bottom of the lake then what is the
depth of the lake
(a) 10 m
(b) 20 m
(C) 60 m
(d) 30 m
Answers
Answered by
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Answer:(b)
Explanation:
Pressure at bottom of the lake =P0+hρg and pressure at half the depth of a lake =P0+h2ρg
According to given condition
P0+12hρg=23(P0+hρg)⇒13P0=16hρg
⇒h=2P0ρg=2×105103×10=20m.
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