if pressure increase by 1% then percentage decrease of volume of an ideal gas at constant temperature is
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Answer:
Answer. S if pressure increased by 1% volume decrease by 100/101 of its initial volume.
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PV = nRT
So,
P1 x V1 = P2 x V2
P x V1 = 1.01 P x V2
So,
V2 = 0.9901 x V1
So an initial volume of, say, one cubic metre would have to change to a volume of 0.9901 cubic metres.
% change = 100 (V1 - V2) / V1
% change = 100 (V1 - 0.9901 x V1) / V1
% change = 0.99 %
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