If pressure of 40 Pa is observed on an area of 200 sq cm , find the force applied.
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Answer:
0.8 N
Explanation:
Given Pressure= 40 Pa
Area= 200 cm^2 = 200 x 10^-4 m^2
Pressure = Force/ Area
40 = F / 200 x 10^-4
F= 40 x 200 x 10^-4
F= 8 x 10^-1
F= 0.8 N
The value of force is 0.8 N
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