If pressure of a gas is reduced by 25% then what should be
the temperature required to make its volume twice at NTP
Answers
Explanation:
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The pressure of a gas is reduced by 25 %.
we have to find the temperature at which the volume of gas would be twice at NTP.
solution : at NTP (normal Temperature and pressure),
temperature , Ti = 20°C = 293K
pressure, Pi = 1 atm
a/c to question, pressure is reduced by 25%
so, pressure becomes, Pf = 0.75 atm
volume of gas becomes twice of its initial.
using equation, PV = nRT
⇒PiVi/PfVf = Ti/Tf
⇒(1atm × V)/(0.75 atm × 2V) = 293K/Tf
⇒1/1.5 = 293/Tf
⇒Tf = 1.5 × 293K = 439.5 K = 166.5°C
Therefore the temperature would be 166.5°C.
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