If pressure of gas collected at water is 715 mm and aqueous tension is 15 mm.What is the
pressure of dry gas?
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1
Mass of organic substance =0.3 g
Volume of Nitrogen collected =50 mL
Temperature (T
1
)=300 K
Vapour pressure of water =15 mm
Actual pressure of dry nitrogen =715−15=700 mm
At STP, we know that P
2
=760 mm and T
2
=273 K then V
2
=?
⟹
T
1
P
1
V
1
=
T
2
P
2
V
2
⟹
300
700×50
=
273
760×V
2
⟹V
2
=41.9 mL
Hence, % of nitrogen =
22400
28×41.9×100
=5.238%≃6.25
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