Question

If prime factorisation of a number is 2 x3, what is the prime factorisation of its cube?​

Answer 1

Answer:

The number of consecutive zeroes are two.

i.e.,

n = 2³×3²×5²×7

= 2×3²×7×(2×5)²

= 12600

Explanation :

Given a natural number n is

2³×3²×5²×7

To get the number consecutive zeroes we must find pairs of (2and 5 ).

Now , Rearranging the prime factors, we get

n = 2³×3²×5²×7

= 2×3²×7×(2²×5²)

= 2×3²×7× (2×5)²

= 2×3²×7×(10)²

= 2×3²×7×(100)

Or

= 12600

Therefore,

The number of consecutive zeroes are two.

i.e.,

n = 2³×3²×5²×7

= 12600

••••

Step-by-step explanation:

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