Question

if principal is ruppes 7500 rate 25% duration 3 years find compount interest.???​

Answer 1

Answer:

example

Step-by-step explanation:

Where A is the amount at the end of time t,

P is the Principal,

t is time,

r is rate

Given,

Rs. 7500 is compounded for two years at the rate of 4% annual interest.

⇒ A = 7500 × 1.042

⇒ A = Rs. 8112

CI = A – P

∴ CI = Rs. (8112 – 7500) = Rs. 612

Answer 2

Given :

• Principal = Rs.7500
• Rate = 25 %
• Duration = 3 years

To Find :

• Compound interest = ?

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SolutioN :

$\dag$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ C.I = P \bigg\{ 1 + \dfrac{R}{100} \bigg\}^n - P }}}}}$

$\dag$ Calculating the Compound Interest :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = P \bigg\{ 1 + \dfrac{R}{100} \bigg\}^n - P } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \bigg\{ 1 + \dfrac{25}{100} \bigg\}^3 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \bigg\{ 1 + \cancel\dfrac{25}{100} \bigg\}^3 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \bigg\{ 1 +0.25 \bigg\}^3 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \bigg\{ 1.25 \bigg\}^3 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \times 1.25 \times 1.25 \times 1.25 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = 7500 \times 1.953125 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { C.I = Rs. \; 14648.43 - 7500 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{{\sf { Compound \; Interest = 7148.43 \bigg( Approx. \bigg) }}}}} \; {\pmb{\purple{\bigstar}}} \\ \\ \\ \end{gathered}$

$\therefore \;$ Compound Interest is Rs.7148.43 (Approx.) .

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