If probability that exactly one of events A B .C occurs is 0.6 and probability that none of A B C occur is 0.2 then probability that ateast two of A B C occur is (A) 0.6 (B) 0.4 (C) 0.8 (D) 0.2
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Probability = 0.6 - 0.2
= 0.4
therefore B part is the correct option
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