If product of ratio is 162 and ratios are 1:2:3. How we find three ratio
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2
this is Ur final answers are 27 , 54 and 81.
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seemasssingh4p893y4:
the answer is wrong.
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1
let us consider the ratios be 1X 2x and 3X
ATQ
![1x \times 2x \times 3x = 162 \\ 6x {}^{3} = 162 \\ x {}^{3} = 162 \div 6 \\ x {}^{3} = 27 \\ x = \sqrt[3]{27} \\ x = \sqrt{3 \times 3 \times 3} \\ x = 3](https://tex.z-dn.net/?f=1x+%5Ctimes+2x+%5Ctimes+3x+%3D+162+%5C%5C+6x+%7B%7D%5E%7B3%7D++%3D+162++%5C%5C+x+%7B%7D%5E%7B3%7D++%3D+162+%5Cdiv+6+%5C%5C+x+%7B%7D%5E%7B3%7D+%3D+27+%5C%5C+x+%3D++%5Csqrt%5B3%5D%7B27%7D+%5C%5C+x+%3D+%5Csqrt%7B3+%5Ctimes+3+%5Ctimes+3%7D++%5C%5C+x+%3D+3 "1x \times 2x \times 3x = 162 \\ 6x {}^{3} = 162 \\ x {}^{3} = 162 \div 6 \\ x {}^{3} = 27 \\ x = \sqrt[3]{27} \\ x = \sqrt{3 \times 3 \times 3} \\ x = 3")
The ratios are 3,6,9.
ATQ
The ratios are 3,6,9.
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