Question

If product of the zeroes of the polynomial kx square+41x+42 is 7 then find the zeroes of the polynomial (k-4)x square+(k+1)x+5

Answer 1

Answer:

-1 and-5/3

Step-by-step explanation:

see photo understand everything

Answer 2

The zeroes of the polynomial is, $x=\frac{-5}{2} or x=-1$

What is a polynomial with example?

• A polynomial is an expression that consists of variables (or indeterminate), terms, exponents and constants.
• For example, 3x2 -2x-10 is a polynomial.

What is polynomial and non polynomial?

• The polynomials can be identified by noting which expressions contain only the operations of addition, subtraction, multiplication, and non-negative integer exponents.
• The non-polynomial expressions will be the expressions which contain other operations.

According to the question:

Given product of root s=7

As per question =$\frac{42}{K}$

$\begin{aligned}&\frac{42}{k}=7 \\&k=6\end{aligned}$

So, the equation is $6 x^{2}+41 x+42$ .

The zeros of required equation.

$\begin{aligned}&(k-4) x^{2}+(k+1) x+5=0 \\&2 x^{2}+7 x+5=0 \\&2 x^{2}+2 x+5 x+5=0 \\&2 x(x+1)+5(x+1)=0 \\&(2 x+5)(x+1)=0 \\&x=\frac{-5}{2} \text { (or) } x=-1\end{aligned}$

Hence, The zeroes of the polynomial is, $x=\frac{-5}{2} or x=-1$

#SPJ2