Physics, asked by Divyamshichalla, 6 months ago

if projection is 45 degrees find range and maximum height

Answers

Answered by mukeshkumar34225

1

Answer:

range= $u^{2}$ sin2α/g= $u^{2}$ /g height= $u^{2}$ $sin^{2}$ α/2g= $u^{2}$ /4 as sinα=1/√2

Explanation:

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