Question

If PS is the median of the triangle with vertices P(2,2) q(6,-1) R(7,3) then equation of the line passing through and parallel to P S is ​

Answer 1

Answer:

2x + 9y + 7 = 0 is the required line .

Step-by-step explanation:

• Median of any triangle divides the opposite line into 2 equal parts

so , S will be mid point .

➡ Apply the mid point formula

• ( a+b)/2

Co-ordinates of S =

$( \frac{7 + 6}{2} , \frac{3 - 1}{2} ) \\ \\ = ( \frac{13}{2} , \frac{1}{1} )$

Slope of the line PS is

y - y1 = m (X - X1)

Putting in the values ,

S = $\frac{ - 2}{9}$

Required equation passes through (1,-1) and parallel to PS is

y - y1 = m (X - X1)

$\implies y + 1 = \frac{ - 2}{9} \times (x - 1) \\ \\ \implies 9y + 9 = - 2x + 2 \\ \\ \implies 2x + 9y + 7 = 0$

Answer 2

Answer:

2x+9y+7=0

here ur answer

please give me a thank and mark me as brainliest