Question

If PT is a tangent drawn from a point P to a circle touching it at T and O is the centre of the circle , Then <OPT +<POT is:

Answer 1

see in the photo
it is according to property that a tangent is perpendicular to the radius of the circle

Answer 2

Answer:

∠OPT + ∠POT = 90°

Step-by-step explanation:

For better understanding of the solution, see the attached figure of the diagram :

Since the tangent drawn to circle is always perpendicular to the radius of the circle.

So, from the diagram, OT ⊥ TP

⇒ ∠OTP = 90°

By using angle sum property of triangle in ΔOTP, We get,

∠OTP + ∠OPT + ∠POT = 180°

⇒ 90° + ∠OPT + ∠POT = 180°

⇒ ∠OPT + ∠POT = 180° - 90°

⇒ ∠OPT + ∠POT = 90°