If pth, qth, and rth term 9d an AP are a, b, c respectively, sjow that (q-r)a+(r-p)b+(p-q)c=0
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Answer:
Hey mate,
Step-by-step explanation:
Sum of n terms of AP is given by,
n/2 * (2a+(n-1)d)
As AP is same , let first term be a Nd common difference be d.
a= p/2(2a+(p-1)d)
b= q/2(2a+(q-1)d)
c = r/2(2a+(r-1)d)
Substituting these values you would get the resultant answer .
Hope it helps you dude.If so tag me as brainliest please.
Have a great day.
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