If pth,qth,rth term of an A. P are a, b, c respectively. Find the value of. a*q-r + b*r-p + c*p-q=???????
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Let a = first term of the AP.
and
Let d = common difference of the AP
Now
a = A+(p-1).d.......(1)
b = A+(q-1).d.......(2)
c = A+(r-1).d........(3)
Subtracting 2nd from 1st , 3rd from 2nd and 1st from 3rd we get
a-b = (p-q).d......(4)
b-c = (q-r).d........(5)
c-a = (r-p).d.......(6)
multiply 4,5,6 by c,a,b respectively we have
c.(a-b) = c.(p-q).d......(4)
a.(b-c) = a.(q-r).d........(5)
b.(c-a) = b.(r-p).d.......(6)
a(q-r).d+b(r-p).d+c(p-q).d = 0(a(q-r)+b(r-p)+c(p-q)).d = 0
Now since d is common difference it should be non zero
Hence
a(q-r)+b(r-p)+c(p-q)= 0
Verified Answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but Verified Answers are the finest of the finest.
Let a = first term of the AP.
and
Let d = common difference of the AP
Now
a = A+(p-1).d.......(1)
b = A+(q-1).d.......(2)
c = A+(r-1).d........(3)
Subtracting 2nd from 1st , 3rd from 2nd and 1st from 3rd we get
a-b = (p-q).d......(4)
b-c = (q-r).d........(5)
c-a = (r-p).d.......(6)
multiply 4,5,6 by c,a,b respectively we have
c.(a-b) = c.(p-q).d......(4)
a.(b-c) = a.(q-r).d........(5)
b.(c-a) = b.(r-p).d.......(6)
a(q-r).d+b(r-p).d+c(p-q).d = 0(a(q-r)+b(r-p)+c(p-q)).d = 0
Now since d is common difference it should be non zero
Hence
a(q-r)+b(r-p)+c(p-q)= 0
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