Question

If pth qth rth terms of an A.P. are a,b,c respectively, then show that
(a-b)r + ( b-c)p + ( c-a)q = 0

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Answer 1

Step-by-step explanation:

LHS=(a-b)r+(b-c)p+(c-a)q

here p=a,q=b,r=c

substitute the values of p,q and r in the given eq

(a-b)c + (b-c)a +(c-a)b

ac-bc+ab-ac+bc-ab

ac-ac-bc+bc+ab-ab

=0

LHS=RHS