Question

if pth term is ap and if qth term is aq . then prove that d =ap-aq÷p-q​

Answer 1

Step-by-step explanation:

IN A AP,

if pth term is in ap and if qth term is aq

$tp = ap = A + (p - 1) D$

$tq = aq = A + (q - 1) D$

TO PROVE:- d =(ap-aq) ÷(p-q)

$now \\ tp - tq = A + (p - 1) D - A - (q - 1) D = a(p - q) \\ = > D(p - 1 - q + 1) =a(p - q) \\ > D = a(p - q) \div (p - q)$

HENCE PROVED.

BEST OF LUCK BUDD.