if pth term is q&q term is p show that nth term is(p+q-n)
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Answer:
pth term = q
a+(p−1)d=q
qth term = p
a+(q−1)d=p
Solving these equations, we get,
d=−1
a=(p+q−1)
Thus,
nth term = a+(n−1)d=(p+q−1)+(n−1)×(−1)=(p+q−n)
Step-by-step explanation:
hope it helpsyou my friend
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